Relationship between RD & TF

Member for

19 years 11 months

Dear Ronald Winter



Thanks for your information



with best wishes

15/1/2006

Member for

22 years 10 months

You need to begin to look past the inputs versus the outputs and see what is actually happening. What are the work day numbers? Calculate early start date, add remaining duration, subtract one and calculate early finish. Translate that into the actual date using the current calendar. If this is too much of a bother, then use MS Project and just tell the Owner, “that’s what the software says it should be.”



Stop trying to come up with general rules to guide you in CPM when the entire process is complex and not amenable to general rules. Good luck!

Member for

20 years 7 months

Thanks for the feedback guys, but my problem is this.



When I increase the RD on one activity, it’s the same activity that shows an impovement in the total float....unlike the example that Joao elicited.



Kashyap

Member for

20 years 4 months

Hello Kahyap,



Now you know that what you thought is not really what the way P3 is acting. This is not the only fundamental in Critical Path scheduling that will give you surprises. There are a lot of them in P3.



If you are doing forensic analysis of the schedule, you may end up confuse. This is because of the relationships that links activities, just complicated.



In this situation, I would suggest that you just do a simple forensic analysis of impacted schedule taking into consideration one event at a time. In this way you will be able to come up with claim entitlement considering only one event. As you evaluated more events, you will arrive at the most advantageous events that will mazimize your claim entitlement.



I hope this will help you, as a start. You can always come back to PP for assistance in the event you got bog down again.



Cheers,



Charlie


Member for

22 years 7 months

Can you be more specific? Namely, what are the relationships?

It can happen with SF. Eg:



T1 5d

T2 10d

T3 5d



T1 - FS - T2

T2 - SF - T3



T1 TF=0; T2 TF=0; T3 TF=5



if RD T2 changes from 10d to 15d, TF of T3 goes from 5d to 10d. The example considers PCT of all task 0%.